How to calculate Cement, Sand, and Aggregate QUANTITY for concrete TA0021

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Added 4 years ago by tomm

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i.e volume of loose Concrete = 1.54 to 1.57 times Volume of dense concrete.

Now calculations is as follows for 1cum(assumed) of Concrete work

ratio Sum = 1+1.5+3=5.5
Shrinkage or safety Factor =1.57 (you can take 1.54 also)

So Total volume of wet concrete required is :- 1.57cum

Volume of broken stone Require = (3/5.5) x 1.57 = 0.856 m3
Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3
Volume of cement = (1/5.5) x 1.57 = 0.285 m3
= 0.285 x1440 = 411 kg

For 1m3 of M20 (1:1.5:3)
Broken stone = 0.856 m3
Sand = 0.472 m3
Cement = 8.22 bag.